p492

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LeetCode p492 Construct the Rectangle 题解

1.题目：

For a web developer, it is very important to know how to design a web page’s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

  1. The area of the rectangular web page you designed must equal to the given target area.

  2. The width W should not be larger than the length L, which means L >= W.

  3. The difference between length L and width W should be as small as possible.
    You need to output the length L and the width W of the web page you designed in sequence.
    Example:
    Input: 4
    Output: [2, 2]
    Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
    But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
    Note:
    The given area won’t exceed 10,000,000 and is a positive integer
    The web page’s width and length you designed must be positive integers.

题意：

输入一个数，输出面积为这个数的矩形的长宽。（L*W)
L>W
要求L与W之间距离越小越好

2.解题思路:

暴力见代码orz

3.代码

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public class Solution {
    public int[] constructRectangle(int area) {
        int[] ans = new int[2];
		int l = (int) Math.sqrt(area);
		
		do {
			int w = area / l;
			if (w * l == area && w <= l) {
				ans[0] = l;
				ans[1] = w;
			//	System.out.println(l + "  " + w);
				break;
			}
			l++;
			
		} while (l <= area);
		return ans;
    }
}

4.一些总结:

感觉还可以分解质因数更快